Question 11

Calculate x(x+y)/y^2-1

Code:

	# Get x
	x = float(input("Please Enter a Value for X"))

	# Get y
	y = float(input("Please Enter a Value for Y"))

	# Calculate top of fraction
	a = x*(x+y)

	# Calculate bottom of fraction
	b = y^2-1

	# Calculate Answer
	ans = a / b

	# Print product
	print("x(x+y)/y^2-1 = ", ans)
	

Output:

x(x+y)/y^2-1 = 0
Charlie M-S